An Indian court sends a top opposition leader, Arvind Kejriwal, to jail until April 15

NEW DELHI (AP) — A court in India on Monday placed a top opposition leader in two weeks of judicial detention after his 10 days in the custody of a federal agency expired, in a case that opposition parties say is part of a crackdown by Prime Minister Narendra Modi’s government on rivals ahead of a national election later this month.

Arvind Kejriwal, the leader of the Aam Aadmi Party, or Common Man’s Party, is the top elected official in the city of New Delhi and one of the country’s most consequential politicians of the past decade.

He was arrested by the federal Enforcement Directorate on March 21. The agency, controlled by Modi’s government, accused Kejriwal’s party and ministers of accepting 1 billion rupees ($12 million) in bribes from liquor contractors nearly two years ago. The arrest triggered days of protests by hundreds of party activists supported by other opposition parties.

The Aam Aadmi Party denied the accusations and said Kejriwal will remain as New Delhi’s chief minister as it fights the case in court. The party is part of a broad alliance of opposition parties called INDIA, which is the main challenger to Modi’s governing Bharatiya Janata Party in the coming elections.

A day after Kejriwal’s arrest, the court remanded him to six days of custody by the Enforcement Directorate that was extended by another four days on Thursday. With the expiration of his detention by the directorate on Monday, the New Delhi court ordered him held in judicial custody until April 15.

Kejriwal’s case has dominated the news in India ahead of the general election, which starts April 19. Opposition parties say the government is misusing federal investigation agencies to harass and weaken its political opponents. They point to a